Option 3 : 2√3

**Given:**

tan θ = 1/√3

**Formula used:**

cosθ = base/hypotenuse

sinθ = perpendicular/hypotenuse

**Calculations:**

tan θ = 1/√3 (perpendicular/base)

cos θ = √3/2 and sin θ = 1/2

Now put these values in asked equations

[(√3 + cos θ)/(cos2 θ + 3 sin θ)] × 3

⇒ [(√3 + (√3/2)]/[(3/4) + (3 × (1/2)] × 3

⇒ [(3√3)/2]/(9/4) × 3

⇒ 2√3

**∴ 2√3 will be the correct answer**